Answer:
Wave number, [tex]k=20\ m^{-1}[/tex]
Explanation:
The given equation of wave is :
[tex]y=0.02\ sin(20x-400t)[/tex]............(1)
The general equation of the wave is given by :
[tex]y=A\ sin(kx-\omega t)[/tex]..............(2)
k is the wave number of the wave
[tex]\omega[/tex] is the angular frequency
On comparing equation (1) and (2) :
[tex]k=20\ m^{-1}[/tex]
[tex]\omega=400\ rad[/tex]
So, the wave number of the wave is [tex]20\ m^{-1}[/tex]. Hence, this is the required solution.
