A strong, weightless rope has a 0.15 kg mass hanging from the middle of it, as in the image. What tension force will make the rope
horizontal, corresponding to 0=0*?
Answers:
0.98 N
• No tension force can do this.
9.8 N
1.5 N

The tension force on the rope that will make it balance horizontal is determined by applying Newton's second law of motion as shown below;

T = mg

where;

g is acceleration due to gravity

T = 0.15 x 9.8

T = 1.47 N

T ≈ 1.5 N

Thus, the tension force on the rope that will make it balance horizontal is 1.5 N.

Learn more about Newton's second law of motion here: https://brainly.com/question/3999427

A strong, weightless rope has a 0.15 kg mass hanging from the middle of it, as in the image. What tension force will make the rope horizontal, corresponding to 0=0*? Answers: 0.98 N • No tension force can do this. 9.8 N 1.5 N

Respuesta :

Otras preguntas

A strong, weightless rope has a 0.15 kg mass hanging from the middle of it, as in the image. What tension force will make the rope
horizontal, corresponding to 0=0*?
Answers:
0.98 N
• No tension force can do this.
9.8 N
1.5 N