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A barrel contains 25 liters of a solvent mixture that is
40%
solvent and 60% water. Lee will add pure solvent
to the barrel, without removing any of the mixture
currently in the barrel, so that the new mixture will
contain 50% solvent and 50% water. How many liters
of pure solvent should Lee add to create this new
mixture?

Respuesta :

michell96

Lee would need to add 5 liters to have a mixture with 50% water and 50%  solvent.

How many water and solvent liters are there in the initial mixture?

It is known the initial mixture contains 25 liters and that it has 60% water and 40% solvent.

Water liters:

  • 25 liters = 100
  • x =  60
  • x = 60 x 25 / 100
  • x = 15 water liters

Solvent liters

  • 25 liters in total - 15 water liters = 10 solvent liters

Now, a 50% rate for both substances implies there is the same number of liters. This means to reach this balance Lee needs to add 5 solvent liters. This would make a mixture with 15 water liters and 15 solvent liters.

Learn more about liters in: https://brainly.com/question/2882095

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